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Multiple Choice
In the crystal structure of MgF₂, how many fluoride ions (anions) are present per unit cell?
A
6
B
2
C
4
D
1
Verified step by step guidance
1
Understand the crystal structure: MgF₂ crystallizes in a structure where magnesium ions (Mg²⁺) and fluoride ions (F⁻) are arranged in a specific pattern. Typically, MgF₂ forms a rutile structure.
Identify the unit cell type: In the rutile structure, each unit cell contains a specific number of cations and anions. For MgF₂, the unit cell is tetragonal.
Determine the number of cations per unit cell: In the rutile structure, there are 2 magnesium ions (Mg²⁺) per unit cell.
Calculate the number of anions per unit cell: Since the chemical formula is MgF₂, for every magnesium ion, there are two fluoride ions. Therefore, with 2 Mg²⁺ ions per unit cell, there should be 2 x 2 = 4 fluoride ions (F⁻) per unit cell.
Conclude the calculation: The number of fluoride ions present per unit cell in the crystal structure of MgF₂ is 4.