What is the mass of 3.45l of gaseous ammonia (NH 3 ) at STP? Round to 3 significant figures.

Hello. In this problem we are told that ozone can oxidize copper in the reaction between copper and ozone to form copper to oxide and oxygen gas fast to calculate the mass of copper required to form 120 ml of oxygen at standard temperature and pressure. So standard temperature is zero degrees Celsius. Standard pressure is one atmosphere standard temperature and pressure. Recall that one mole of any gas. In this case we're dealing with oxygen occupies a volume of 22.4 liters. This is referred to as its smaller volume. So make use of that relationship in our calculation. But we'll begin with 100 and 20 ml of oxygen, which is what's being formed will convert our volume from male leaders. Two leaders and then we can make use of our Mueller volume and then we can then go to our balanced reaction equation. Now that we have moles of oxygen. So one mole of oxygen is produced for every one mole of copper that reacts And we'll convert them to massive copper. Using its molar mass, one molar copper has a mass is 63.546g. So our milliliters of oxygen cancels liters of oxygen cancels moles of oxygen cancels moles of copper cancels and we're left with grams of copper. This works out to then 0.340 g of copper. Thanks for watching. Hope this helps