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Multiple Choice
At a certain temperature, the equilibrium constant Kc for the reaction 2 C(s) + O2(g) ⇌ 2 CO(g) is 4.72. What is the equilibrium constant Kc for the reverse reaction CO(g) ⇌ C(s) + 0.5 O2(g) at the same temperature?
A
9.44
B
2.36
C
0.212
D
4.72
Verified step by step guidance
1
Understand that the equilibrium constant (Kc) for a reaction is related to the concentrations of the products and reactants at equilibrium. For the given reaction, 2 C(s) + O2(g) ⇌ 2 CO(g), the Kc is 4.72.
Recognize that reversing a chemical reaction involves inverting the equilibrium constant. If the forward reaction has an equilibrium constant Kc, the reverse reaction will have an equilibrium constant of 1/Kc.
Write the expression for the reverse reaction: CO(g) ⇌ C(s) + 0.5 O2(g). Note that the stoichiometry of the reverse reaction is different from the forward reaction.
Calculate the equilibrium constant for the reverse reaction by taking the reciprocal of the Kc for the forward reaction. Use the formula: Kc(reverse) = 1/Kc(forward).
Substitute the given Kc value for the forward reaction into the formula: Kc(reverse) = 1/4.72. This will give you the equilibrium constant for the reverse reaction.