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Multiple Choice
In the presence of heat or light, chloromethane gas will react with a stoichiometric amount of chlorine gas to produce which of the following products? CH3Cl (g) + Cl2 (g) →
A
CH2Cl2 (g) + HCl (g)
B
CHCl3 (g)+ HCl (g)
C
CCl4 (g) + HCl (g)
D
CHCl3 (g) + H2 (g)
E
CH3Cl (g) + Cl2 (g)
Verified step by step guidance
1
Identify the type of reaction: This is a substitution reaction where chlorine atoms replace hydrogen atoms in chloromethane.
Understand the mechanism: In the presence of heat or light, chlorine molecules dissociate into radicals, which initiate the substitution process.
Consider the stoichiometry: Each chlorine molecule can replace one hydrogen atom in chloromethane, forming hydrochloric acid (HCl) as a byproduct.
Predict the products: Depending on the extent of substitution, multiple products can form, such as dichloromethane (CH2Cl2), trichloromethane (CHCl3), or tetrachloromethane (CCl4).
Evaluate the options: Compare the given options with the possible products from the substitution reaction to determine which matches the expected outcome.