What is the identity of the acid (H 3 X) identified via titration of Na 3 X with HCl?

Hi everyone here we have a question telling us a 0.385 g sample of weak die protic acid is tight traded against 0.220 molar sodium hydroxide, 38.8 mL of sodium hydroxide is required to reach the end point of the filtration, calculate the molar mass and grams per mole of the acid. So what is this reaction gonna look like Armani product acid? We're going to call H two a. And we're going to react with sodium hydroxide and that's going to form In a two a plus water. Now we need to balance this reaction. If we notice on our reactive side we have one sodium, we're on the products that we have to. So we're gonna put a two in front of their and now we need to balance our oxygen and hydrogen and we can do that by putting a two in front of our water. So now we need to calculate the moles of sodium hydroxide and 38. mL of 0.22 molar sodium hydroxide. We do that by taking our 0.8 mL of sodium hydroxide. And we're going to multiply that by one l Over 1000 ml to change it to leaders And then times 0. 20 moles over one leader because polarity is moles over. Leader and our middle. Leaders are going to cancel out Our leaders are going to cancel out and it's going to give us 0. eight five three six moles. So we have two moles of sodium hydroxide for every one mole of our di product acid. So we're going to take our zero 0. 08536 moles And divided by two, which equals 0. moles of our die protic acid. So 0.004268 moles of our die protic acid has a mass of 0.385g. So we have one mole of die protic acid is going to equal one mold, Divided by 0. moles Time 0.385g. And that's gonna equal 90. Graham's Permal. And that is our final answer. Thank you for watching. Bye.