Multiple Choice
What is the oxidation number of manganese in MnO2?
6. Chemical Quantities & Aqueous Reactions
Calculate Oxidation Numbers
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Join thousands of students who trust us to help them ace their exams!Watch the first videoMultiple Choice
What is the oxidation state of the central metal in Na2[V(C2O4)3]?
A
+4
B
+2
C
+3
D
+5
Verified step by step guidance1
Identify the overall charge of the complex ion. In this case, Na2[V(C2O4)3] is a neutral compound, so the sum of the charges of all components must equal zero.
Determine the charge of the sodium ions (Na+). Since there are two sodium ions, their total charge is 2(+1) = +2.
Identify the charge of the oxalate ion (C2O4^2-). Each oxalate ion has a charge of -2, and there are three oxalate ions, so their total charge is 3(-2) = -6.
Set up an equation to find the oxidation state of vanadium (V). Let x be the oxidation state of vanadium. The equation is: 2(+1) + x + 3(-2) = 0.
Solve the equation for x to find the oxidation state of vanadium. This will give you the oxidation state of the central metal in the complex.
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