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Multiple Choice
When 0.112 g of heptene, C7H14, is burned in a bomb calorimeter, the temperature rises by 4.99 °C. The heat capacity of the calorimeter is 2.46 kJ/°C. Calculate the combustion energy (ΔE) for heptene, C7H14, in kJ/g. Express your answer in kJ/g.
A
-98.3 kJ/g
B
-115.2 kJ/g
C
-120.7 kJ/g
D
-109.5 kJ/g
Verified step by step guidance
1
Step 1: Understand the problem. We need to calculate the combustion energy (ΔE) for heptene, C7H14, in kJ/g using the data provided from the bomb calorimeter experiment.
Step 2: Use the formula for heat transfer in a calorimeter: \( q = C \times \Delta T \), where \( q \) is the heat absorbed or released, \( C \) is the heat capacity of the calorimeter, and \( \Delta T \) is the change in temperature.
Step 3: Substitute the given values into the formula: \( q = 2.46 \text{ kJ/°C} \times 4.99 \text{ °C} \). This will give you the total heat released during the combustion of heptene.
Step 4: Calculate the combustion energy per gram of heptene. Use the formula \( \Delta E = \frac{q}{ ext{mass of heptene}} \). Substitute \( q \) from Step 3 and the mass of heptene (0.112 g) into the formula.
Step 5: Express the result in kJ/g. This will give you the combustion energy of heptene in kJ/g, which you can compare to the provided options to identify the correct answer.