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Ch.13 - Solutions & Their Properties
Chapter 13, Problem 149e

Treatment of 1.385 g of an unknown metal M with an excess of aqueous HCl evolved a gas that was found to have a volume of 382.6 mL at 20.0 °C and 755 mm Hg pressure. Heating the reaction mixture to evaporate the water and remaining HCl then gave a white crystalline compound, MClx. After dis- solving the compound in 25.0 g of water, the melting point of the resulting solution was - 3.53 °C. (e) What are the formula and molecular weight of MClx?

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Step 1: Use the ideal gas law to determine the number of moles of gas evolved. Convert the given volume of gas to liters, temperature to Kelvin, and pressure to atmospheres. Use the formula: \( PV = nRT \), where \( R \) is the ideal gas constant.
Step 2: Determine the number of moles of HCl that reacted with the metal M. Since the gas evolved is likely hydrogen, use the stoichiometry of the reaction between metal M and HCl to find the moles of M that reacted.
Step 3: Calculate the molality of the solution using the freezing point depression formula: \( \Delta T_f = i \cdot K_f \cdot m \), where \( \Delta T_f \) is the change in freezing point, \( i \) is the van't Hoff factor, \( K_f \) is the cryoscopic constant for water, and \( m \) is the molality. Solve for \( m \).
Step 4: Use the molality to find the moles of MClx in the solution. Since molality is moles of solute per kilogram of solvent, use the mass of water to find the moles of MClx.
Step 5: Determine the formula and molecular weight of MClx by comparing the moles of M from the gas evolution with the moles of MClx from the freezing point depression. Use the ratio to find \( x \) in MClx and calculate the molar mass.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Ideal Gas Law

The Ideal Gas Law relates the pressure, volume, temperature, and number of moles of a gas through the equation PV = nRT. This law is essential for calculating the number of moles of gas evolved during the reaction, which can be determined from the given volume, temperature, and pressure of the gas. Understanding this relationship allows for the determination of the amount of metal M that reacted with HCl.
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Colligative Properties

Colligative properties are properties of solutions that depend on the number of solute particles in a given amount of solvent, rather than the identity of the solute. The freezing point depression observed in the solution formed after dissolving MClx in water can be used to calculate the molality of the solution, which is crucial for determining the number of moles of MClx and, subsequently, the molecular weight of the compound.
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Stoichiometry

Stoichiometry involves the calculation of reactants and products in chemical reactions based on balanced chemical equations. In this context, stoichiometry is used to relate the moles of the metal M that reacted with HCl to the moles of MClx produced. Understanding stoichiometric relationships is vital for determining the formula of MClx and calculating its molecular weight based on the mass of the unknown metal.
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Related Practice
Textbook Question
Addition of 50.00 mL of 2.238 m H2SO4 1solution density= 1.1243 g>mL2 to 50.00 mL of 2.238 M BaCl2 gives a white precipitate.(b) If you filter the mixture and add more H2SO4 solution to the filtrate, would you obtain more precipitate? Explain.
Textbook Question

Treatment of 1.385 g of an unknown metal M with an excess of aqueous HCl evolved a gas that was found to have a volume of 382.6 mL at 20.0 °C and 755 mm Hg pressure. Heating the reaction mixture to evaporate the water and remaining HCl then gave a white crystalline compound, MClx. After dissolving the compound in 25.0 g of water, the melting point of the resulting solution was - 3.53 °C. (b) What mass of MClx is formed? (a) How many moles of H2 gas are evolved?

Textbook Question

Treatment of 1.385 g of an unknown metal M with an excess of aqueous HCl evolved a gas that was found to have a volume of 382.6 mL at 20.0 °C and 755 mm Hg pressure. Heating the reaction mixture to evaporate the water and remaining HCl then gave a white crystalline compound, MClx. After dis- solving the compound in 25.0 g of water, the melting point of the resulting solution was - 3.53 °C. (c) What is the molality of particles (ions) in the solution of MClx?

Textbook Question

Treatment of 1.385 g of an unknown metal M with an excess of aqueous HCl evolved a gas that was found to have a volume of 382.6 mL at 20.0 °C and 755 mm Hg pressure. Heating the reaction mixture to evaporate the water and remaining HCl then gave a white crystalline compound, MClx. After dis- solving the compound in 25.0 g of water, the melting point of the resulting solution was - 3.53 °C. (f) What is the identity of the metal M?

Textbook Question

A compound that contains only C and H was burned in excess O2 to give CO2 and H2O. When 0.270 g of the com- pound was burned, the amount of CO2 formed reacted completely with 20.0 mL of 2.00 M NaOH solution according to the equation 2 OH-1aq2 + CO21g2 S CO 2- 1aq2 + H2O1l2 When 0.270 g of the compound was dissolved in 50.0 g of camphor, the resulting solution had a freezing point of 177.9 °C. [#Pure camphor freezes at 179.8 °C and has Kf = 37.7 1°C kg2>mol.] (a) What is the empirical formula of the compound?