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Multiple Choice
Suppose 0.0350 g Mg is reacted with 10.00 mL of 6 M HCl to produce aqueous magnesium chloride and hydrogen gas. Mg(s) + 2HCl(aq) → MgCl2(aq) + H2(g). What is the limiting reactant in this reaction?
A
Magnesium
B
Hydrochloric acid
Verified step by step guidance
1
First, calculate the moles of magnesium (Mg) using its molar mass. The molar mass of Mg is approximately 24.31 g/mol. Use the formula: \( \text{moles of Mg} = \frac{\text{mass of Mg}}{\text{molar mass of Mg}} \).
Next, calculate the moles of hydrochloric acid (HCl) using its concentration and volume. The concentration is given as 6 M, and the volume is 10.00 mL. Convert the volume to liters by dividing by 1000. Use the formula: \( \text{moles of HCl} = \text{concentration} \times \text{volume in liters} \).
Now, use the stoichiometry of the balanced chemical equation \( \text{Mg(s) + 2HCl(aq) → MgCl2(aq) + H2(g)} \) to determine the mole ratio between Mg and HCl. According to the equation, 1 mole of Mg reacts with 2 moles of HCl.
Compare the calculated moles of Mg and HCl to determine the limiting reactant. The limiting reactant is the one that will be completely consumed first, based on the stoichiometric ratios.
Finally, identify the limiting reactant by comparing the available moles of each reactant to the required stoichiometric ratio. The reactant with fewer moles than required by the stoichiometry is the limiting reactant.