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Multiple Choice
Kc = 6.5 x 102 at a particular temperature for a reaction: 2 NO(g) + 2 H(g) ⇌ N2(g) + 2 H2O(g). Calculate Kc at same temperature for the following reaction: 1/3 N2(g) + 2/3 H2O(g) ⇌ 2/3 NO(g) + 2/3 H(g).
A
8.7
B
0.12
C
0.54
D
3.6×10–9
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1
Identify the original reaction and its equilibrium constant (Kc): 2 NO(g) + 2 H(g) ⇌ N2(g) + 2 H2O(g) with Kc = 6.5 x 10^2.
Recognize that the new reaction is a transformation of the original reaction. The new reaction is: 1/3 N2(g) + 2/3 H2O(g) ⇌ 2/3 NO(g) + 2/3 H(g).
Determine the relationship between the original and new reactions. Notice that the new reaction is the reverse of the original reaction, scaled by a factor of 1/3.
Apply the rule for reversing a reaction: If a reaction is reversed, the new Kc is the reciprocal of the original Kc. Therefore, for the reverse reaction, Kc' = 1 / (Kc).
Apply the rule for scaling a reaction: If a reaction is scaled by a factor of n, the new Kc is the original Kc raised to the power of 1/n. Therefore, for the scaled reaction, Kc'' = (Kc')^(1/3).