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Multiple Choice
Based on your understanding of the solubility rules, which of the following ionic compounds will be insoluble?
A
Zinc chloride
B
Manganese (V) chlorate
C
Lead (II) sulfate
D
Gallium acetate
Verified step by step guidance
1
Step 1: Review the solubility rules for common ionic compounds. Solubility rules help predict whether a compound will dissolve in water.
Step 2: Identify the ions present in each compound. For example, Zinc chloride contains Zn²⁺ and Cl⁻ ions, Manganese (V) chlorate contains Mn⁵⁺ and ClO₃⁻ ions, Lead (II) sulfate contains Pb²⁺ and SO₄²⁻ ions, and Gallium acetate contains Ga³⁺ and C₂H₃O₂⁻ ions.
Step 3: Apply the solubility rules to each compound. Generally, chlorides (Cl⁻) are soluble except for those of silver, lead, and mercury. Sulfates (SO₄²⁻) are soluble except for those of barium, lead, and calcium.
Step 4: Determine the solubility of each compound based on the rules. Zinc chloride is soluble because chlorides are generally soluble. Manganese (V) chlorate is soluble because chlorates are generally soluble. Gallium acetate is soluble because acetates are generally soluble.
Step 5: Conclude that Lead (II) sulfate is insoluble because sulfates are generally soluble except for those of lead, barium, and calcium, making it the correct answer.