Table of contents

1. Intro to General Chemistry3h 48m
2. Atoms & Elements4h 16m
3. Chemical Reactions4h 10m
4. BONUS: Lab Techniques and Procedures1h 38m
5. BONUS: Mathematical Operations and Functions48m
6. Chemical Quantities & Aqueous Reactions3h 53m
7. Gases3h 49m
8. Thermochemistry2h 37m
9. Quantum Mechanics2h 58m
10. Periodic Properties of the Elements3h 9m
11. Bonding & Molecular Structure3h 29m
12. Molecular Shapes & Valence Bond Theory1h 57m
13. Liquids, Solids & Intermolecular Forces2h 23m
14. Solutions3h 1m
15. Chemical Kinetics2h 53m
16. Chemical Equilibrium2h 29m
17. Acid and Base Equilibrium5h 1m
18. Aqueous Equilibrium4h 47m
19. Chemical Thermodynamics1h 50m
20. Electrochemistry2h 42m
21. Nuclear Chemistry2h 36m
22. Organic Chemistry5h 7m
23. Chemistry of the Nonmetals2h 39m
24. Transition Metals and Coordination Compounds3h 16m

6. Chemical Quantities & Aqueous Reactions

Molarity

General Chemistry

6. Chemical Quantities & Aqueous Reactions

Molarity

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Multiple Choice

Hypernatremia is a medical condition where a patient has high levels of sodium in their blood, and is the result of the body containing too little water. A patient has a measured sodium level of 165 mM. If 30.0 mL of their blood were drawn, what mass (in ng) of sodium would be present?

1.14x10⁷ ng

1.14x10⁶ ng

1.14x10⁸ ng

4.18x10⁸ ng

4.18x10⁶ ng

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Verified step by step guidance

Start by understanding the concentration given: 165 mM, which means 165 millimoles of sodium per liter of blood.

Convert the volume of blood drawn from milliliters to liters. Since 1 mL = 0.001 L, 30.0 mL is equivalent to 0.030 L.

Calculate the number of millimoles of sodium in the 30.0 mL of blood using the formula: \( \text{millimoles of sodium} = \text{concentration} \times \text{volume} \). Substitute the values: \( 165 \text{ mM} \times 0.030 \text{ L} \).

Convert millimoles of sodium to moles by using the conversion factor: 1 millimole = 0.001 mole.

Finally, convert moles of sodium to mass in nanograms. Use the molar mass of sodium (approximately 23 g/mol) and the conversion factors: 1 g = 10^9 ng. Calculate the mass using the formula: \( \text{mass} = \text{moles} \times \text{molar mass} \times 10^9 \).