Table of contents

1. Intro to General Chemistry3h 48m
2. Atoms & Elements4h 16m
3. Chemical Reactions4h 10m
4. BONUS: Lab Techniques and Procedures1h 38m
5. BONUS: Mathematical Operations and Functions48m
6. Chemical Quantities & Aqueous Reactions3h 53m
7. Gases3h 49m
8. Thermochemistry2h 37m
9. Quantum Mechanics2h 58m
10. Periodic Properties of the Elements3h 9m
11. Bonding & Molecular Structure3h 29m
12. Molecular Shapes & Valence Bond Theory1h 57m
13. Liquids, Solids & Intermolecular Forces2h 23m
14. Solutions3h 1m
15. Chemical Kinetics2h 53m
16. Chemical Equilibrium2h 29m
17. Acid and Base Equilibrium5h 1m
18. Aqueous Equilibrium4h 47m
19. Chemical Thermodynamics1h 50m
20. Electrochemistry2h 42m
21. Nuclear Chemistry2h 36m
22. Organic Chemistry5h 7m
23. Chemistry of the Nonmetals2h 39m
24. Transition Metals and Coordination Compounds3h 16m

2. Atoms & Elements

Ions

General Chemistry

2. Atoms & Elements

Ions

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Multiple Choice

Which of the following would most likely form an anion with a 2– charge?

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Verified step by step guidance

Step 1: Understand the concept of anions. Anions are negatively charged ions formed when an atom gains electrons. The charge of the anion is determined by the number of electrons gained.

Step 2: Identify the group in the periodic table where elements typically form anions with a 2- charge. Elements in Group 16 (the oxygen group) often form anions with a 2- charge because they tend to gain two electrons to achieve a stable electron configuration.

Step 3: Examine the elements provided in the problem: K (Potassium), Ca (Calcium), Sc (Scandium), Se (Selenium), Br (Bromine), and Kr (Krypton). Determine which of these elements belong to Group 16.

Step 4: Recognize that Selenium (Se) is in Group 16 of the periodic table. Elements in this group typically gain two electrons to form anions with a 2- charge.

Step 5: Conclude that Selenium (Se) is the element most likely to form an anion with a 2- charge, based on its position in the periodic table and its tendency to gain electrons.