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Ch.4 - Reactions in Aqueous Solution
Chapter 4, Problem 88b

A solution is made by mixing 15.0 g of Sr(OH)2 and 55.0 mL of 0.200 M HNO3. b. Calculate the concentration of each ion remaining in solution.

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1
Determine the moles of Sr(OH)_2 using its molar mass.
Calculate the moles of HNO_3 using its concentration and volume.
Write the balanced chemical equation for the reaction: Sr(OH)_2 + 2HNO_3 → Sr(NO_3)_2 + 2H_2O.
Identify the limiting reactant by comparing the mole ratio from the balanced equation.
Calculate the concentration of each ion remaining in solution by considering the stoichiometry of the reaction and the total volume of the solution.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Stoichiometry

Stoichiometry is the calculation of reactants and products in chemical reactions. It involves using balanced chemical equations to determine the relationships between the amounts of substances consumed and produced. In this question, stoichiometry will help in determining how much of each reactant reacts and what remains in solution after the reaction.
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Ion Concentration

Ion concentration refers to the amount of a specific ion present in a solution, typically expressed in molarity (M). To find the concentration of ions remaining after a reaction, one must consider the initial concentrations, the volume of the solution, and the stoichiometry of the reaction. This concept is crucial for calculating the final concentrations of Sr²⁺ and NO₃⁻ ions in the solution.
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Neutralization Reaction

A neutralization reaction occurs when an acid reacts with a base to produce water and a salt. In this case, HNO3 (an acid) reacts with Sr(OH)2 (a base) to form Sr(NO3)2 and water. Understanding this concept is essential for predicting the products of the reaction and determining how much of each reactant is left unreacted in the solution.
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