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Multiple Choice
Given the following chemical reaction, A → B. If the concentration of A is doubled the rate increases by a factor of 2.83, what is the order of the reaction with respect to A.
A
1
B
0.5
C
1.5
D
0
E
2
Verified step by step guidance
1
Identify the rate law expression for the reaction: Rate = k[A]^n, where k is the rate constant, [A] is the concentration of A, and n is the order of the reaction with respect to A.
Understand that when the concentration of A is doubled, the rate increases by a factor of 2.83. This can be expressed as: (2[A])^n = 2.83 * ([A])^n.
Simplify the expression: 2^n = 2.83.
To find the order of the reaction (n), take the logarithm of both sides: log(2^n) = log(2.83).
Use the logarithmic identity log(a^b) = b*log(a) to solve for n: n * log(2) = log(2.83). Then, solve for n by dividing both sides by log(2).