Table of contents

1. Intro to General Chemistry3h 48m
2. Atoms & Elements4h 16m
3. Chemical Reactions4h 10m
4. BONUS: Lab Techniques and Procedures1h 38m
5. BONUS: Mathematical Operations and Functions48m
6. Chemical Quantities & Aqueous Reactions3h 53m
7. Gases3h 49m
8. Thermochemistry2h 37m
9. Quantum Mechanics2h 58m
10. Periodic Properties of the Elements3h 9m
11. Bonding & Molecular Structure3h 29m
12. Molecular Shapes & Valence Bond Theory1h 57m
13. Liquids, Solids & Intermolecular Forces2h 23m
14. Solutions3h 1m
15. Chemical Kinetics2h 53m
16. Chemical Equilibrium2h 29m
17. Acid and Base Equilibrium5h 1m
18. Aqueous Equilibrium4h 47m
19. Chemical Thermodynamics1h 50m
20. Electrochemistry2h 42m
21. Nuclear Chemistry2h 36m
22. Organic Chemistry5h 7m
23. Chemistry of the Nonmetals2h 39m
24. Transition Metals and Coordination Compounds3h 16m

3. Chemical Reactions

Stoichiometry

General Chemistry

3. Chemical Reactions

Stoichiometry

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Multiple Choice

If a match contained 1.00 g of P, how much P₄O₁₀ would form if the following equation was obeyed?_ KClO₃ + _ P → 10 KCl + ___ P₄O₁₀

36.7 g

8.07 × 10^–3 g

2.29 g

9.17 g

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Verified step by step guidance

First, balance the chemical equation. The reaction given is: \( \text{KClO}_3 + \text{P} \rightarrow \text{KCl} + \text{P}_4\text{O}_{10} \). To balance it, ensure the number of atoms of each element is the same on both sides of the equation.

Identify the molar mass of phosphorus (P) and tetraphosphorus decoxide (P4O10). The molar mass of phosphorus (P) is approximately 30.97 g/mol, and the molar mass of P4O10 is approximately 283.88 g/mol.

Convert the mass of phosphorus given (1.00 g) to moles using the molar mass of phosphorus. Use the formula: \( \text{moles of P} = \frac{\text{mass of P}}{\text{molar mass of P}} \).

Use the stoichiometry of the balanced equation to find the moles of P4O10 produced. From the balanced equation, determine the mole ratio between P and P4O10.

Convert the moles of P4O10 to grams using its molar mass. Use the formula: \( \text{mass of P4O10} = \text{moles of P4O10} \times \text{molar mass of P4O10} \).