Textbook Question
Identify the oxidation state of the metal in each of the following compounds.
(a) (NH4)3[RhCl6]
(b) [Cr(NH3)4(SCN)2]Br
(c) [Cu(en)2]SO4
(d) Na2[Mn(EDTA)]
24. Transition Metals and Coordination Compounds
Ligands
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Join thousands of students who trust us to help them ace their exams!Watch the first videoMultiple Choice
Ethylenediamine (shown below) would be called a __________.
A
dentate
B
bidentate
C
tridentate
D
Tetradentate
E
polydentate
Verified step by step guidance1
Examine the structure of ethylenediamine, which consists of two nitrogen atoms each bonded to two hydrogen atoms and connected by a two-carbon chain.
Understand the concept of denticity, which refers to the number of donor atoms in a ligand that can bind to a central metal atom or ion in a coordination complex.
Identify the donor atoms in ethylenediamine. In this case, the two nitrogen atoms can each donate a pair of electrons to form coordinate bonds with a metal center.
Determine the denticity of ethylenediamine by counting the number of donor atoms. Since there are two nitrogen atoms capable of binding, ethylenediamine is a bidentate ligand.
Conclude that ethylenediamine is called a bidentate ligand because it can form two bonds with a metal center through its two nitrogen atoms.
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