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Multiple Choice
What is the expression for the equilibrium constant (Kb) for the dissociation of a weak base in water?
A
Kb = [BH+][H2O] / [B][OH-]
B
Kb = [B][OH-] / [BH+]
C
Kb = [BH+][OH-] / [B]
D
Kb = [B][H2O] / [BH+][OH-]
Verified step by step guidance
1
Identify the general reaction for the dissociation of a weak base (B) in water: B + H2O ⇌ BH+ + OH-. This reaction shows the base (B) accepting a proton from water to form its conjugate acid (BH+) and hydroxide ions (OH-).
Understand that the equilibrium constant for a base dissociation, Kb, is defined in terms of the concentrations of the products and reactants at equilibrium.
Write the expression for the equilibrium constant (Kb) based on the reaction: Kb = ([BH+][OH-]) / [B]. This expression is derived from the law of mass action, which states that the equilibrium constant is the ratio of the product of the concentrations of the products to the product of the concentrations of the reactants, each raised to the power of their stoichiometric coefficients.
Note that water (H2O) is a pure liquid and its concentration is not included in the equilibrium expression. In equilibrium expressions, the concentrations of pure solids and liquids are omitted because they are constant.
Verify that the correct expression for Kb is Kb = ([BH+][OH-]) / [B], which matches the given correct answer. This confirms that the expression accounts for the concentrations of the ions formed and the initial base.