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Multiple Choice
A Se ion has a mass number of 75 and a charge of -2. Determine the number of neutrons, protons, and electrons in this ion.
A
34 neutrons, 41 protons, 36 electrons
B
41 neutrons, 36 protons, 34 electrons
C
41 neutrons, 34 protons, 36 electrons
D
41 neutrons, 34 protons, 32 electrons
Verified step by step guidance
1
Identify the atomic number of selenium (Se) from the periodic table, which is 34. This represents the number of protons in the atom.
Since the ion has a charge of -2, it has gained 2 extra electrons compared to the neutral atom. Therefore, calculate the number of electrons by adding 2 to the atomic number: 34 + 2 = 36 electrons.
The mass number of the ion is given as 75. The mass number is the sum of protons and neutrons in the nucleus. Use the formula: \( \text{Mass Number} = \text{Protons} + \text{Neutrons} \).
Substitute the known values into the formula to find the number of neutrons: \( 75 = 34 + \text{Neutrons} \). Solve for neutrons: \( \text{Neutrons} = 75 - 34 \).
Calculate the number of neutrons: \( \text{Neutrons} = 41 \). Therefore, the Se ion has 41 neutrons, 34 protons, and 36 electrons.