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Multiple Choice
Given that the heat of fusion of water is 6.02 kJ/mol, the heat capacity of H2O(l) is 75.2 J/mol·K, and the heat capacity of H2O(s) is 37.7 J/mol·K, calculate the total heat required to convert 1 mole of ice at -10°C to liquid water at 0°C.
A
5.52 kJ
B
6.52 kJ
C
7.02 kJ
D
6.02 kJ
Verified step by step guidance
1
Calculate the heat required to raise the temperature of ice from -10°C to 0°C using the formula q = m * C * ΔT, where m is the number of moles, C is the heat capacity of ice, and ΔT is the change in temperature.
Substitute the given values into the formula: m = 1 mol, C = 37.7 J/mol·K, and ΔT = 0°C - (-10°C) = 10 K.
Convert the calculated heat from joules to kilojoules by dividing by 1000, since 1 kJ = 1000 J.
Add the heat of fusion to the heat calculated in the previous step. The heat of fusion is the energy required to convert ice at 0°C to liquid water at 0°C, which is given as 6.02 kJ/mol.
Sum the heat required to raise the temperature of ice and the heat of fusion to find the total heat required for the entire process.