Table of contents

1. Intro to General Chemistry3h 48m
2. Atoms & Elements4h 16m
3. Chemical Reactions4h 10m
4. BONUS: Lab Techniques and Procedures1h 38m
5. BONUS: Mathematical Operations and Functions48m
6. Chemical Quantities & Aqueous Reactions3h 53m
7. Gases3h 49m
8. Thermochemistry2h 37m
9. Quantum Mechanics2h 58m
10. Periodic Properties of the Elements3h 9m
11. Bonding & Molecular Structure3h 29m
12. Molecular Shapes & Valence Bond Theory1h 57m
13. Liquids, Solids & Intermolecular Forces2h 23m
14. Solutions3h 1m
15. Chemical Kinetics2h 53m
16. Chemical Equilibrium2h 29m
17. Acid and Base Equilibrium5h 1m
18. Aqueous Equilibrium4h 47m
19. Chemical Thermodynamics1h 50m
20. Electrochemistry2h 42m
21. Nuclear Chemistry2h 36m
22. Organic Chemistry5h 7m
23. Chemistry of the Nonmetals2h 39m
24. Transition Metals and Coordination Compounds3h 16m

15. Chemical Kinetics

Arrhenius Equation

General Chemistry

15. Chemical Kinetics

Arrhenius Equation

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Multiple Choice

Using the Arrhenius Equation, calculate the frequency factor (A) for the reaction NO2(g) + CO(g) → NO(g) + CO2(g) given the activation energy Ea = 1.50 × 10² kJ/mol, and rate constants k1 = 2.57 M⁻¹·s⁻¹ at 701 K and k2 = 567 M⁻¹·s⁻¹ at 895 K.

A = 1.2 × 10¹⁰ M⁻¹·s⁻¹

A = 5.8 × 10⁸ M⁻¹·s⁻¹

A = 7.9 × 10¹¹ M⁻¹·s⁻¹

A = 3.5 × 10¹² M⁻¹·s⁻¹

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Verified step by step guidance

Start by understanding the Arrhenius Equation: k = A * e^(-Ea/(R*T)), where k is the rate constant, A is the frequency factor, Ea is the activation energy, R is the gas constant (8.314 J/(mol*K)), and T is the temperature in Kelvin.

Convert the activation energy from kJ/mol to J/mol by multiplying by 1000. So, Ea = 1.50 × 10² kJ/mol * 1000 = 1.50 × 10⁵ J/mol.

Use the Arrhenius Equation in its logarithmic form to solve for A: ln(k) = ln(A) - Ea/(R*T). Rearrange to find ln(A) = ln(k) + Ea/(R*T).

Substitute the given values for k1 and T1 into the equation: ln(A) = ln(2.57) + (1.50 × 10⁵)/(8.314 * 701). Calculate this expression to find ln(A) for the first set of conditions.

Repeat the substitution for k2 and T2: ln(A) = ln(567) + (1.50 × 10⁵)/(8.314 * 895). Calculate this expression to find ln(A) for the second set of conditions. Compare the results to determine the most consistent value of A from the given options.