Textbook Question
Two electromagnetic waves are represented below. (
(a) Which wave has the greater intensity?
9. Quantum Mechanics
Wavelength and Frequency
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Calculate the wavelength (in nm) of the blue light emitted by a mercury lamp with a frequency of 6.32 × 10^14 Hz. (Use the speed of light, c = 3.00 × 10^8 m/s)
A
532 nm
B
650 nm
C
589 nm
D
474 nm
Verified step by step guidance1
Understand the relationship between frequency and wavelength using the formula: \( c = \lambda \nu \), where \( c \) is the speed of light, \( \lambda \) is the wavelength, and \( \nu \) is the frequency.
Rearrange the formula to solve for wavelength \( \lambda \): \( \lambda = \frac{c}{\nu} \).
Substitute the given values into the equation: \( c = 3.00 \times 10^8 \text{ m/s} \) and \( \nu = 6.32 \times 10^{14} \text{ Hz} \).
Calculate the wavelength \( \lambda \) in meters by dividing the speed of light by the frequency.
Convert the wavelength from meters to nanometers by multiplying the result by \( 1 \times 10^9 \) (since 1 m = 1,000,000,000 nm).
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