Join thousands of students who trust us to help them ace their exams!Watch the first video
Multiple Choice
A solution is prepared by dissolving 23.7 g of CaCl2 in 375 g of water. The density of the resulting solution is 1.05 g/mL. What is the molarity of Cl⁻ ions in this solution?
A
0.66 M
B
1.32 M
C
0.44 M
D
0.88 M
Verified step by step guidance
1
Calculate the moles of CaCl₂: First, determine the molar mass of CaCl₂ by adding the atomic masses of calcium (Ca) and chlorine (Cl). The molar mass of CaCl₂ is approximately 110.98 g/mol. Use the formula: \( \text{moles of CaCl}_2 = \frac{\text{mass of CaCl}_2}{\text{molar mass of CaCl}_2} \) to find the moles of CaCl₂.
Determine the moles of Cl⁻ ions: Since each formula unit of CaCl₂ produces two Cl⁻ ions, multiply the moles of CaCl₂ by 2 to find the moles of Cl⁻ ions.
Calculate the total volume of the solution: Use the density of the solution to find its volume. The total mass of the solution is the sum of the mass of CaCl₂ and the mass of water. Use the formula: \( \text{volume} = \frac{\text{mass of solution}}{\text{density}} \) to find the volume in milliliters, then convert it to liters.
Calculate the molarity of Cl⁻ ions: Molarity is defined as moles of solute per liter of solution. Use the formula: \( \text{Molarity} = \frac{\text{moles of Cl}^-}{\text{volume of solution in liters}} \) to find the molarity of Cl⁻ ions.
Verify the answer: Compare the calculated molarity with the given options to ensure the correct answer is selected.