When nitrogen and tin (Sn 4+ ) form an ionic compound, what is the formula?

Hey everyone, we're asked to provide the formula of the ionic compound formed from the following pairs for our first one, we have silver and iodine. Looking at our periodic table, silver has a plus one charge and iodine has a minus one charge. Using our criss Cross method, we're going to multiply each ion by the oxidation number of the other ion and vice versa. So I dine has an oxidation number of one, so we will have one of silver and silver has an oxidation number of one as well. So we will have one of iodine. Now let's go ahead and look at our second one, we have potassium and sulfur. Now potassium has a charge of plus one since it's in our group one A and sulfur has a charge of minus two since it's in our group six A. Now using our criss cross method again, our potassium will have a subscript of two since it's being multiplied by sulfur oxidation number of two, and sulfur will have A subscript of one, Since potassium is oxidation number is one. Now looking at our third one, we have aluminum and oxygen, aluminum has a charge of plus three, while oxygen has a charge of minus two. Again, using our criss Cross method, we're going to have a subscript of two for aluminum since we're multiplying aluminum by the oxidation number of oxygen and oxygen will have a subscript of three. Next looking at our last one, we have magnesium and nitrogen. Magnesium has a charge of plus two. While nitrogen has a charge of -3. Using our criss cross method, magnesium will have a subscript of three, while nitrogen has a subscript of two. And these will be our final answers. Now, I hope this made sense and let us know if you have any questions.