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Multiple Choice
A solution is prepared by dissolving 28.4 g of glucose (C6H12O6) in 355 g of water. The final volume of the solution is 378 mL. What is the molarity of the solution?
A
0.417 M
B
0.500 M
C
1.000 M
D
0.750 M
Verified step by step guidance
1
Calculate the molar mass of glucose (C6H12O6) by adding the atomic masses of all the atoms: 6 carbon atoms, 12 hydrogen atoms, and 6 oxygen atoms. Use the periodic table to find the atomic masses: Carbon (C) = 12.01 g/mol, Hydrogen (H) = 1.01 g/mol, Oxygen (O) = 16.00 g/mol.
Determine the number of moles of glucose by dividing the mass of glucose (28.4 g) by its molar mass. Use the formula: \( \text{moles of glucose} = \frac{\text{mass of glucose}}{\text{molar mass of glucose}} \).
Convert the volume of the solution from milliliters to liters, since molarity is expressed in moles per liter. Use the conversion: 1 L = 1000 mL.
Calculate the molarity of the solution using the formula: \( \text{Molarity (M)} = \frac{\text{moles of solute}}{\text{volume of solution in liters}} \). Substitute the number of moles of glucose and the volume of the solution in liters into this formula.
Compare the calculated molarity with the given options to determine the correct answer.