Join thousands of students who trust us to help them ace their exams!Watch the first video
Multiple Choice
Calculate the energy of a neutron whose de Broglie wavelength is 0.7 Å. Assume the mass of the neutron is 1.675 x 10^-27 kg and use Planck's constant h = 6.626 x 10^-34 J·s.
A
3.8 x 10^-21 J
B
7.4 x 10^-23 J
C
5.6 x 10^-22 J
D
1.2 x 10^-20 J
Verified step by step guidance
1
Start by understanding the de Broglie wavelength formula: \( \lambda = \frac{h}{mv} \), where \( \lambda \) is the wavelength, \( h \) is Planck's constant, \( m \) is the mass, and \( v \) is the velocity of the particle.
Rearrange the de Broglie equation to solve for velocity \( v \): \( v = \frac{h}{m\lambda} \). Substitute the given values: \( h = 6.626 \times 10^{-34} \) J·s, \( m = 1.675 \times 10^{-27} \) kg, and \( \lambda = 0.7 \times 10^{-10} \) m (since 1 Å = 10^{-10} m).
Calculate the velocity \( v \) using the rearranged formula: \( v = \frac{6.626 \times 10^{-34}}{1.675 \times 10^{-27} \times 0.7 \times 10^{-10}} \).
Once you have the velocity, use the kinetic energy formula \( KE = \frac{1}{2}mv^2 \) to find the energy of the neutron. Substitute the mass \( m = 1.675 \times 10^{-27} \) kg and the calculated velocity \( v \).
Calculate the kinetic energy \( KE \) using the formula: \( KE = \frac{1}{2} \times 1.675 \times 10^{-27} \times v^2 \). This will give you the energy of the neutron in joules.