Textbook Question
Dichloroethylene 1C2H2Cl22 has three forms (isomers), each of which is a different substance. (c) How many isomeric forms can chloroethylene, C2H3Cl, have? Would they be expected to have dipole moments?
Table of contents
- 1. Intro to General Chemistry3h 48m
- Classification of Matter18m
- Physical & Chemical Changes19m
- Chemical Properties7m
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- 2. Atoms & Elements4h 16m
- The Atom9m
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- Ions27m
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- Periodic Table: Classifications11m
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- 10. Periodic Properties of the Elements3h 9m
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- 22. Organic Chemistry5h 7m
- Introduction to Organic Chemistry8m
- Structural Formula8m
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- Intro to Hydrocarbons16m
- Isomers11m
- Chirality15m
- Functional Groups in Chemistry11m
- Naming Alkanes4m
- The Alkyl Groups9m
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- Naming Cyclic Alkanes6m
- Naming Other Substituents8m
- Naming Alcohols11m
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- Naming Ketones5m
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- Naming Carboxylic Acids4m
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- Naming Benzene7m
- Alkane Reactions7m
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- 23. Chemistry of the Nonmetals2h 39m
- Main Group Elements: Bonding Types4m
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- The Electron Configuration Review16m
- Periodic Table Charges Review20m
- Hydrogen Isotopes4m
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- Production of Hydrogen8m
- Group 1A and 2A Reactions7m
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- Oxides, Peroxides, and Superoxides12m
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- Noble Gas Compounds3m
- 24. Transition Metals and Coordination Compounds3h 16m
- Atomic Radius & Density of Transition Metals11m
- Electron Configurations of Transition Metals7m
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- Paramagnetism and Diamagnetism10m
- Ligands10m
- Complex Ions5m
- Coordination Complexes7m
- Classification of Ligands11m
- Coordination Numbers & Geometry9m
- Naming Coordination Compounds22m
- Writing Formulas of Coordination Compounds8m
- Isomerism in Coordination Complexes14m
- Orientations of D Orbitals4m
- Intro to Crystal Field Theory10m
- Crystal Field Theory: Octahedral Complexes5m
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- Crystal Field Theory: Square Planar Complexes4m
- Crystal Field Theory Summary8m
- Magnetic Properties of Complex Ions9m
- Strong-Field vs Weak-Field Ligands6m
- Magnetic Properties of Complex Ions: Octahedral Complexes11m
22. Organic Chemistry
Naming Other Substituents
Struggling with General Chemistry?
Join thousands of students who trust us to help them ace their exams!Watch the first videoMultiple Choice
Draw a structure for the following alkane: 3-tert-butyl-1-phenylheptane.
A
B
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D
Verified step by step guidance1
Identify the main chain: The name '3-tert-butyl-1-phenylheptane' indicates that the main chain is heptane, which consists of 7 carbon atoms in a straight chain.
Locate the substituents: The name specifies two substituents: a tert-butyl group at the 3rd carbon and a phenyl group at the 1st carbon of the heptane chain.
Draw the heptane chain: Start by drawing a straight chain of 7 carbon atoms, which represents heptane.
Add the tert-butyl group: At the 3rd carbon of the heptane chain, attach a tert-butyl group. A tert-butyl group is a branched structure consisting of three methyl groups attached to a central carbon.
Add the phenyl group: At the 1st carbon of the heptane chain, attach a phenyl group. A phenyl group is a benzene ring, which is a hexagonal ring of six carbon atoms with alternating double bonds.
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