Table of contents

1. Intro to General Chemistry3h 48m
2. Atoms & Elements4h 16m
3. Chemical Reactions4h 10m
4. BONUS: Lab Techniques and Procedures1h 38m
5. BONUS: Mathematical Operations and Functions48m
6. Chemical Quantities & Aqueous Reactions3h 53m
7. Gases3h 49m
8. Thermochemistry2h 37m
9. Quantum Mechanics2h 58m
10. Periodic Properties of the Elements3h 9m
11. Bonding & Molecular Structure3h 29m
12. Molecular Shapes & Valence Bond Theory1h 57m
13. Liquids, Solids & Intermolecular Forces2h 23m
14. Solutions3h 1m
15. Chemical Kinetics2h 53m
16. Chemical Equilibrium2h 29m
17. Acid and Base Equilibrium5h 1m
18. Aqueous Equilibrium4h 47m
19. Chemical Thermodynamics1h 50m
20. Electrochemistry2h 42m
21. Nuclear Chemistry2h 36m
22. Organic Chemistry5h 7m
23. Chemistry of the Nonmetals2h 39m
24. Transition Metals and Coordination Compounds3h 16m

3. Chemical Reactions

Balancing Chemical Equations

General Chemistry

3. Chemical Reactions

Balancing Chemical Equations

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Multiple Choice

Which of the following is the balanced chemical equation for the hydrolysis of antimony trichloride (SbCl3)?

SbCl3 + 2H2O → Sb(OH)3 + 2HCl

SbCl3 + 3H2O → Sb(OH)3 + 3HCl

SbCl3 + 4H2O → Sb(OH)3 + 4HCl

SbCl3 + H2O → Sb(OH)3 + HCl

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Verified step by step guidance

Identify the reactants and products in the chemical reaction. The reactants are antimony trichloride (SbCl3) and water (H2O), and the products are antimony hydroxide (Sb(OH)3) and hydrochloric acid (HCl).

Write the unbalanced chemical equation: SbCl3 + H2O → Sb(OH)3 + HCl.

Count the number of each type of atom on both sides of the equation. Initially, you have 1 Sb, 3 Cl, and 1 O on the left, and 1 Sb, 3 O, and 1 Cl on the right.

Balance the chlorine atoms by ensuring the number of Cl atoms on both sides is equal. Since there are 3 Cl atoms in SbCl3, you need 3 HCl molecules on the right side: SbCl3 + H2O → Sb(OH)3 + 3HCl.

Balance the oxygen and hydrogen atoms. You need 3 water molecules to provide 3 oxygen atoms for Sb(OH)3 and 6 hydrogen atoms to balance with 3 HCl molecules: SbCl3 + 3H2O → Sb(OH)3 + 3HCl.