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Multiple Choice
Which of the following is the correct Lewis structure for the phosphate ion (PO4^3-) including formal charges?
A
A central phosphorus atom double-bonded to one oxygen atom and single-bonded to three oxygen atoms, with the three single-bonded oxygens each carrying a -1 formal charge.
B
A central phosphorus atom double-bonded to two oxygen atoms and single-bonded to two oxygen atoms, with the two single-bonded oxygens each carrying a -1 formal charge.
C
A central phosphorus atom single-bonded to four oxygen atoms, with each oxygen atom carrying a -1 formal charge.
D
A central phosphorus atom single-bonded to four oxygen atoms, with no formal charges on any atoms.
Verified step by step guidance
1
Identify the total number of valence electrons in the phosphate ion (PO4^3-). Phosphorus (P) has 5 valence electrons, each oxygen (O) has 6 valence electrons, and the ion has an additional 3 electrons due to the -3 charge. Calculate the total: 5 + (4 * 6) + 3 = 32 valence electrons.
Determine the central atom, which is typically the least electronegative element. In this case, phosphorus (P) is the central atom.
Arrange the oxygen atoms around the phosphorus atom and distribute the electrons to form bonds. Start by forming single bonds between the phosphorus and each oxygen atom, using 8 electrons (2 electrons per bond).
Distribute the remaining electrons to satisfy the octet rule for each oxygen atom. After forming single bonds, 24 electrons remain. Distribute these electrons to the oxygen atoms, giving each oxygen atom 6 additional electrons to complete their octets.
Calculate the formal charges for each atom. The formal charge is calculated as: Formal Charge = (Valence electrons) - (Non-bonding electrons) - (Bonding electrons/2). For the structure with a double bond to one oxygen, the formal charges are: P = 0, double-bonded O = 0, and each single-bonded O = -1. Verify that the sum of formal charges equals the overall charge of the ion, which is -3.