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Multiple Choice
What is the molar solubility of Fe(OH)2 at 25°C if the Ksp of the compound is 7.9 × 10⁻¹⁶?
A
5.6 × 10⁻⁷ M
B
2.8 × 10⁻⁸ M
C
3.9 × 10⁻⁵ M
D
1.3 × 10⁻⁶ M
Verified step by step guidance
1
Start by writing the balanced dissolution equation for Fe(OH)₂: Fe(OH)₂(s) ⇌ Fe²⁺(aq) + 2OH⁻(aq). This equation shows that one mole of Fe(OH)₂ dissolves to produce one mole of Fe²⁺ ions and two moles of OH⁻ ions.
Define the molar solubility of Fe(OH)₂ as 's'. This means that the concentration of Fe²⁺ ions in solution will be 's' and the concentration of OH⁻ ions will be '2s' due to the stoichiometry of the dissolution reaction.
Write the expression for the solubility product constant (Ksp) for Fe(OH)₂: Ksp = [Fe²⁺][OH⁻]². Substitute the concentrations from the previous step into this expression: Ksp = (s)(2s)².
Simplify the expression: Ksp = 4s³. This equation relates the Ksp value to the molar solubility 's'.
Solve for 's' by substituting the given Ksp value (7.9 × 10⁻¹⁶) into the equation: 7.9 × 10⁻¹⁶ = 4s³. Rearrange the equation to find 's', which represents the molar solubility of Fe(OH)₂.