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Multiple Choice
Using the method of initial rates for the reaction A → B, if the initial concentration of A is doubled and the rate of reaction quadruples, what is the order of reaction with respect to A?
A
Third order
B
Zero order
C
Second order
D
First order
Verified step by step guidance
1
Identify the relationship between the change in concentration and the change in rate. Here, doubling the concentration of A results in the rate quadrupling.
Express the rate law for the reaction: \( \text{Rate} = k[A]^n \), where \( n \) is the order of the reaction with respect to A.
Set up the equation based on the given data: \( 4 \times \text{Rate}_1 = k(2[A]_1)^n \).
Recognize that the original rate is \( \text{Rate}_1 = k[A]_1^n \). Substitute this into the equation: \( 4k[A]_1^n = k(2[A]_1)^n \).
Simplify the equation: \( 4 = 2^n \). Solve for \( n \) to determine the order of the reaction with respect to A.