Table of contents

1. Intro to General Chemistry3h 48m
2. Atoms & Elements4h 16m
3. Chemical Reactions4h 10m
4. BONUS: Lab Techniques and Procedures1h 36m
5. BONUS: Mathematical Operations and Functions48m
6. Chemical Quantities & Aqueous Reactions3h 53m
7. Gases3h 49m
8. Thermochemistry2h 37m
9. Quantum Mechanics2h 58m
10. Periodic Properties of the Elements3h 9m
11. Bonding & Molecular Structure3h 29m
12. Molecular Shapes & Valence Bond Theory1h 57m
13. Liquids, Solids & Intermolecular Forces2h 23m
14. Solutions3h 1m
15. Chemical Kinetics2h 53m
16. Chemical Equilibrium2h 29m
17. Acid and Base Equilibrium5h 1m
18. Aqueous Equilibrium4h 47m
19. Chemical Thermodynamics1h 50m
20. Electrochemistry2h 42m
21. Nuclear Chemistry2h 36m
22. Organic Chemistry5h 7m
23. Chemistry of the Nonmetals2h 39m
24. Transition Metals and Coordination Compounds3h 16m

18. Aqueous Equilibrium

Acid-Base Indicators

General Chemistry

18. Aqueous Equilibrium

Acid-Base Indicators

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Multiple Choice

Complete neutralization of 12.5 mL of Sr(OH)₂ requires 36 mL of 0.1 M HCl. What is the concentration of the Sr(OH)₂ solution?

0.288 M

0.036 M

0.144 M

0.072 M

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Verified step by step guidance

Write the balanced chemical equation for the neutralization reaction: \( \text{Sr(OH)}_2 + 2\text{HCl} \rightarrow \text{SrCl}_2 + 2\text{H}_2\text{O} \). This shows that one mole of \( \text{Sr(OH)}_2 \) reacts with two moles of \( \text{HCl} \).

Calculate the moles of \( \text{HCl} \) used in the reaction. Use the formula: \( \text{moles} = \text{concentration} \times \text{volume} \). Here, the concentration of \( \text{HCl} \) is 0.1 M and the volume is 36 mL (convert to liters by dividing by 1000).

Determine the moles of \( \text{Sr(OH)}_2 \) that reacted. From the balanced equation, 1 mole of \( \text{Sr(OH)}_2 \) reacts with 2 moles of \( \text{HCl} \). Use the stoichiometric ratio to find the moles of \( \text{Sr(OH)}_2 \).

Calculate the concentration of the \( \text{Sr(OH)}_2 \) solution. Use the formula: \( \text{concentration} = \frac{\text{moles}}{\text{volume}} \). The volume of \( \text{Sr(OH)}_2 \) is 12.5 mL (convert to liters by dividing by 1000).

Verify the calculation by checking the units and ensuring that the stoichiometry and conversion factors are correctly applied. This will confirm the concentration of the \( \text{Sr(OH)}_2 \) solution.