Multiple Choice
What is the molarity of a NaCl solution prepared by dissolving 0.159 mol of NaCl in 350 mL of solution?
6. Chemical Quantities & Aqueous Reactions
Molarity
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What is the molarity of an AlBr₃ solution if 150.0 mL of the solution contains 250.0 mg of Br⁻ ion?
A
0.0054 M
B
0.0108 M
C
0.0027 M
D
0.0018 M
Verified step by step guidance1
Convert the mass of Br⁻ ions from milligrams to grams by dividing by 1000. This is necessary because molarity calculations require the mass in grams.
Calculate the moles of Br⁻ ions using the formula: \( \text{moles} = \frac{\text{mass (g)}}{\text{molar mass of Br⁻}} \). The molar mass of Br⁻ is approximately 79.9 g/mol.
Determine the moles of AlBr₃ in the solution. Since each AlBr₃ molecule dissociates into three Br⁻ ions, divide the moles of Br⁻ by 3 to find the moles of AlBr₃.
Convert the volume of the solution from milliliters to liters by dividing by 1000, as molarity is expressed in terms of liters.
Calculate the molarity of the AlBr₃ solution using the formula: \( \text{Molarity (M)} = \frac{\text{moles of AlBr₃}}{\text{volume of solution in liters}} \).
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