Multiple Choice
Given the reaction 3 N2H4(l) -> 4 NH3(g) + N2(g), how many moles of N2H4 are required to produce 2.39 moles of NH3?
3. Chemical Reactions
Stoichiometry
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A 10.0 mL solution of 0.121 M H₂SO₄ is neutralized by 17.1 mL of KOH solution. What is the molarity of the KOH solution?
A
0.242 M
B
0.071 M
C
0.142 M
D
0.121 M
Verified step by step guidance1
Start by writing the balanced chemical equation for the neutralization reaction between sulfuric acid (H₂SO₄) and potassium hydroxide (KOH):
Determine the moles of H₂SO₄ in the solution using the formula:
Convert the volume from mL to L:
Calculate moles of H₂SO₄:
Use the stoichiometry of the balanced equation to find the moles of KOH required to neutralize the moles of H₂SO₄. According to the equation, 2 moles of KOH are needed for every mole of H₂SO₄. Therefore, multiply the moles of H₂SO₄ by 2 to find the moles of KOH.
Calculate the molarity of the KOH solution using the formula:
Convert the volume of KOH from mL to L:
Substitute the moles of KOH and the volume in liters into the molarity formula to find the molarity of the KOH solution.
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