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1. Intro to General Chemistry3h 48m
2. Atoms & Elements4h 16m
3. Chemical Reactions4h 10m
4. BONUS: Lab Techniques and Procedures1h 38m
5. BONUS: Mathematical Operations and Functions48m
6. Chemical Quantities & Aqueous Reactions3h 53m
7. Gases3h 49m
8. Thermochemistry2h 37m
9. Quantum Mechanics2h 58m
10. Periodic Properties of the Elements3h 9m
11. Bonding & Molecular Structure3h 29m
12. Molecular Shapes & Valence Bond Theory1h 57m
13. Liquids, Solids & Intermolecular Forces2h 23m
14. Solutions3h 1m
15. Chemical Kinetics2h 53m
16. Chemical Equilibrium2h 29m
17. Acid and Base Equilibrium5h 1m
18. Aqueous Equilibrium4h 47m
19. Chemical Thermodynamics1h 50m
20. Electrochemistry2h 42m
21. Nuclear Chemistry2h 36m
22. Organic Chemistry5h 7m
23. Chemistry of the Nonmetals2h 39m
24. Transition Metals and Coordination Compounds3h 16m

6. Chemical Quantities & Aqueous Reactions

Molecular Equations

General Chemistry

6. Chemical Quantities & Aqueous Reactions

Molecular Equations

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Multiple Choice

What is the net ionic equation for the reaction between formic acid (HCHO2) and potassium hydroxide (KOH) in aqueous solution?

HCHO2(aq) + KOH(aq) → KCHO2(aq) + H2O(l)

H⁺(aq) + OH⁻(aq) → H2O(l)

HCHO2(aq) + K⁺(aq) + OH⁻(aq) → KCHO2(aq) + H2O(l)

HCHO2(aq) + OH⁻(aq) → CHO2⁻(aq) + H2O(l)

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Verified step by step guidance

Identify the reactants and products in the given chemical equation: HCHO2(aq) + KOH(aq) → KCHO2(aq) + H2O(l).

Write the complete ionic equation by dissociating all strong electrolytes into their ions: HCHO2(aq) + K⁺(aq) + OH⁻(aq) → K⁺(aq) + CHO2⁻(aq) + H2O(l).

Identify the spectator ions, which are ions that appear on both sides of the equation without undergoing any change. In this case, K⁺(aq) is the spectator ion.

Remove the spectator ions from the complete ionic equation to derive the net ionic equation: HCHO2(aq) + OH⁻(aq) → CHO2⁻(aq) + H2O(l).

Verify that the net ionic equation is balanced in terms of both mass and charge, ensuring that the number of atoms and the total charge are the same on both sides of the equation.