Table of contents
- 1. Chemical Measurements1h 50m
- 2. Tools of the Trade1h 17m
- 3. Experimental Error1h 52m
- 4 & 5. Statistics, Quality Assurance and Calibration Methods1h 57m
- 6. Chemical Equilibrium3h 41m
- 7. Activity and the Systematic Treatment of Equilibrium1h 0m
- 8. Monoprotic Acid-Base Equilibria1h 53m
- 9. Polyprotic Acid-Base Equilibria2h 17m
- 10. Acid-Base Titrations2h 37m
- 11. EDTA Titrations1h 34m
- 12. Advanced Topics in Equilibrium1h 16m
- 13. Fundamentals of Electrochemistry2h 19m
- 14. Electrodes and Potentiometry41m
- 15. Redox Titrations1h 14m
- 16. Electroanalytical Techniques57m
- 17. Fundamentals of Spectrophotometry50m
4 & 5. Statistics, Quality Assurance and Calibration Methods
The Gaussian Distribution
Struggling with Analytical Chemistry?
Join thousands of students who trust us to help them ace their exams!Watch the first videoMultiple Choice
From EXAMPLE 1, determine the percentage of final grades that would lie between 88 to 92.
A
5.36 %
B
5.33 %
C
5.39 %
D
5.49 %

1
Identify the distribution type of the final grades. If it's a normal distribution, you can use the properties of the normal distribution to find the percentage of grades between two values.
Determine the mean (μ) and standard deviation (σ) of the distribution from EXAMPLE 1. These values are crucial for calculating probabilities in a normal distribution.
Convert the raw scores (88 and 92) to z-scores using the formula: z = (X - μ) / σ, where X is the score you are converting.
Use the standard normal distribution table (z-table) to find the probability corresponding to each z-score. This will give you the cumulative probability for each score.
Subtract the cumulative probability of the lower z-score (for 88) from the cumulative probability of the higher z-score (for 92) to find the percentage of grades that lie between 88 and 92.
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The Gaussian Distribution practice set
