Table of contents
- 1. Chemical Measurements1h 50m
- 2. Tools of the Trade1h 17m
- 3. Experimental Error1h 52m
- 4 & 5. Statistics, Quality Assurance and Calibration Methods1h 57m
- 6. Chemical Equilibrium3h 41m
- 7. Activity and the Systematic Treatment of Equilibrium1h 0m
- 8. Monoprotic Acid-Base Equilibria1h 53m
- 9. Polyprotic Acid-Base Equilibria2h 17m
- 10. Acid-Base Titrations2h 37m
- 11. EDTA Titrations1h 34m
- 12. Advanced Topics in Equilibrium1h 16m
- 13. Fundamentals of Electrochemistry2h 19m
- 14. Electrodes and Potentiometry41m
- 15. Redox Titrations1h 14m
- 16. Electroanalytical Techniques57m
- 17. Fundamentals of Spectrophotometry50m
7. Activity and the Systematic Treatment of Equilibrium
Ionic Strength of Soluble Salts
Struggling with Analytical Chemistry?
Join thousands of students who trust us to help them ace their exams!Watch the first videoMultiple Choice
Calculate the ionic strength for the following ionic compound.
0.04 M SnO2
A
0.40
B
0.48
C
0.12
D
0.96
E
0.24

1
Identify the ions present in the compound SnO2. Tin(IV) oxide dissociates into Sn^{4+} and O^{2-} ions in solution.
Determine the concentration of each ion in the solution. Given that the concentration of SnO2 is 0.04 M, the concentration of Sn^{4+} ions is 0.04 M, and the concentration of O^{2-} ions is 0.08 M (since each SnO2 produces two O^{2-} ions).
Use the formula for ionic strength: I = \frac{1}{2} \sum c_i z_i^2, where c_i is the concentration of each ion and z_i is the charge of each ion.
Substitute the concentrations and charges into the formula: I = \frac{1}{2} [(0.04)(4)^2 + (0.08)(2)^2].
Calculate the ionic strength by evaluating the expression, ensuring to square the charges and multiply by the respective concentrations before summing and dividing by 2.
Related Videos
0
Ionic Strength of Soluble Salts practice set
