Table of contents
- 1. Chemical Measurements1h 50m
- 2. Tools of the Trade1h 17m
- 3. Experimental Error1h 52m
- 4 & 5. Statistics, Quality Assurance and Calibration Methods1h 57m
- 6. Chemical Equilibrium3h 41m
- 7. Activity and the Systematic Treatment of Equilibrium1h 0m
- 8. Monoprotic Acid-Base Equilibria1h 53m
- 9. Polyprotic Acid-Base Equilibria2h 17m
- 10. Acid-Base Titrations2h 37m
- 11. EDTA Titrations1h 34m
- 12. Advanced Topics in Equilibrium1h 16m
- 13. Fundamentals of Electrochemistry2h 19m
- 14. Electrodes and Potentiometry41m
- 15. Redox Titrations1h 14m
- 16. Electroanalytical Techniques57m
- 17. Fundamentals of Spectrophotometry50m
12. Advanced Topics in Equilibrium
General Approach to Acid-Base Systems
Struggling with Analytical Chemistry?
Join thousands of students who trust us to help them ace their exams!Watch the first videoMultiple Choice
Determine the pH of a 6.7 x 10 -8 M NaOH.
A
7.17
B
7.14
C
6.82
D
7.57

1
Identify that NaOH is a strong base, which dissociates completely in water to produce OH⁻ ions.
Calculate the concentration of OH⁻ ions, which is equal to the concentration of NaOH, i.e., 6.7 x 10⁻⁸ M.
Use the formula for pOH: \( \text{pOH} = -\log[\text{OH}^-] \) to find the pOH of the solution.
Convert pOH to pH using the relationship: \( \text{pH} = 14 - \text{pOH} \).
Consider the effect of water's autoionization, especially since the concentration of NaOH is very low, and adjust the pH accordingly if necessary.
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General Approach to Acid-Base Systems practice set
